1) (Х^2+5Х)/(Х+3)=4 2) (2Х+3)/(Х+2)=(3Х+2)/Х

Question

1) (Х^2+5Х)/(Х+3)=4

2) (2Х+3)/(Х+2)=(3Х+2)/Х

Answer 1

1)(х²+5х)/(х+3)=4 х≠-3
х²+5х-4(х+3)=0
х²+5х-4х-12=0
х²+х-12=0
Д=1+48=7²
х1=-1+7/2=3
х2=-1-7/2=-4
х1=3, х2=-4
2)(2х+3)/(х+2)=(3х+2)/х х≠-2 х≠0
(2х+3)х-(3х²+6х+2х+2)=0
2х²+3х-3х²-8х-4=0
х²+5х+4=0
Д=25-16=3²
х1=-5+3/2=-1
х2=-5-3/2=-4
х1=-1, х2=-4,х≠-2, х≠0.