ПОМОГИТЕ 1,,,,,2,,,,,3

№1

а) $(\frac{2}{3} + \frac{4}{7} )*42= \frac{26}{21} * \frac{42}{1} =52$

б) $(2 \frac{1}{4} -1 \frac{1}{2} )*8=( \frac{9}{4} - \frac{3}{2} )*8= \frac{3}{4} * \frac{8}{1} =6$

№2

$4 \frac{1}{6}*3 \frac{2}{7} +2 \frac{5}{7} *4 \frac{1}{6} = \frac{25}{6} * \frac{23}{7} + \frac{19}{7} * \frac{25}{6} = \frac{575}{42} + \frac{475}{42} = \frac{1050}{42} = 25$

№3

$2 \frac{1}{3} x-1 \frac{1}{2} x+ \frac{1}{6} x= \frac{7}{3} x- \frac{3}{2} x+ \frac{1}{6} x= \frac{14}{6} x- \frac{9}{6}x + \frac{1}{6} x= \frac{6}{6} x = 1*x= x$