Решение
у= (2x-3)
-----------------
³√(x³-8x+4)
y = u/v
y` = (u`v - v`u)/v²
u = 2x - 3
v = ∛(x³ - 8x + 4)
y` = {2*∛(x³ - 8x + 4) - [(1/3)*(x³ - 8x + 4)¹/³⁻¹ * (3x² - 8)] * (2x - 3)} / [∛(x³ - 8x + 4)]² = {2*∛(x³ - 8x + 4) - [(3x² - 8)*(2x - 3)] } / [3 * ∛(x³ - 8x + 4)²]} / [∛(x³ - 8x + 4)]²