M(Zn)=3.25гm(HCl)=5гm(ZnCl2)-?уравнение реакций Zn+2HCl=ZnCl2+H2

Question

M(Zn)=3.25г
m(HCl)=5г
m(ZnCl2)-?
уравнение реакций Zn+2HCl=ZnCl2+H2

Answer 1

N(Zn)= m/M= 3.25/65=0.05
1/0.05= x/0.05
x=1
m(ZnCl2)=n*M= 0.05*(65+35.5*2)=6.8