[tex]\frac{2x+3}{3}-\frac{x+1}{4}\ \textless \ -1\\\\ \frac{(2x+3)*4}{3*4}-\frac{(x+1)*3}{4*3}+\frac{1*4*3}{4*3}\ \textless \ 0\\\\ \frac{4(2x+3)-3(x+1)+12}{4*3}\ \textless \ 0\\\\ 8x+12-3x-3+12\ \textless \ 0\\\\ 5x-3\ \textless \ 0\\\\ 5x\ \textless \ 3\\\\ x\ \textless \ \frac{5}{3}=\frac{1*3+2}{3}=\frac{1*3}{3}+\frac{2}{3}=1+\frac{2}{3}=1\frac{2}{3}[/tex]
Ответ: [tex]1[/tex]