1/2+1/4+1/8+1/16+1/32+1/64+1/128=?

Question

1/2+1/4+1/8+1/16+1/32+1/64+1/128=?

Answer 1

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Answer 2

1/2;1/4;1/8;1/16;1/32;1/64;1/128 это геометрическое прогрессии
b1=1/2;q=1/2;|q|<1<br>S(7)=b1/(1-q)=1/2*1/1/2=1