Решите систему уравнений способом подставления { 10p+7q=-2 {2p-22=5q

$\left \{ {{10p+7q=-2} \atop {2p-22=5q}} \right. \left \{ {{10p+7q=-2} \atop {p-2,5q=11}} \right.\\\\ \left \{ {{p=11+2,5q} \atop {10(11+2,5q)+7q=-2}} \right.\\\\ \left \{ {{p=11+2,5q} \atop {110+25q+7q=-2}} \right.\\\\ \left \{ {{p=11+2,5q} \atop {32q=-112}} \right. \\\\ \left \{ {{q=-3,5} \atop {p=11+2,5*(-3,5)}} \right.\\\\ \left \{ {{q=-3,5} \atop {p=11-8,75}} \right.\\\\ \left \{ {{p=2,25} \atop {q=-3,5}} \right.$
Ответ: (2,25 ; - 3,5)