1) 3x^2+13x-10 = 0
D = √(13^2-4*3*(-10) = √(169+120) = √289 = 17
x1 = (-13+17)/3*2 = 4/6 = 2/3
x2 = (-13-17)/3*2 =-30/6 = -5
Ответ: x1 = 2/3, x2 = -5
2) 2x^2-3x=0
x(2x-3) = 0
x1 = 0 , x2 = 3/2
Ответ: x1 = 0, x2 = 3/2
3) 2(x+3)(x-1/2)=0
(x+3)(2x-1)=0
x1=-3, x2=1/2
Ответ: x1=-3, x2=1/2