14(целых)*(1/2+1/3+1/4)=?

1 вар.
$14 \times ( \frac{1}{2} + \frac{1}{3} + \frac{1}{4} ) = \frac{14}{2} + \frac{14}{3} + \frac{14}{4} = 7 + 4 \frac{2}{3} + \frac{7}{2} = 11 \frac{2}{3} + 3 \frac{1}{2} = 14 \frac{2 \times 2 + 3}{6} = 14 \frac{7}{6} = 15 \frac{1}{6}$
2 вар.
$14 \times ( \frac{1}{2} + \frac{1}{3} + \frac{1}{4} ) = 14 \times \frac{6 + 4 + 3}{12} = 14 \times \frac{13}{12} = \frac{14 \times 13}{12} = \frac{7 \times 13}{6} = \frac{91}{6} = 15 \frac{1}{6}$