СРОЧНО!!! Arccos(x-0.5)-arcsin(x-0.5)=(3pi)/2

Question

СРОЧНО!!! Arccos(x-0.5)-arcsin(x-0.5)=(3pi)/2

Answer 1

Arcin(y)+arcos(y)=pi/2
arccos(x-0.5)=pi/2-arcsin(x-0.5)
подставлю в условие
pi/2-arcsin(x-0.5)-arcsin(x-0.5)=3pi/2
-2arcsin(x-0.50=pi
arcsin(x-0.5)= -pi/2
x-0.5=sin(-pi/20= -1
x= -1+0.5= -0.5