Дано: m(AlCL3)-5g H2SO4 Узнать m(Al2(SO4)3)-? V(HCL)-?
2AlCl3 + 3H2SO4 = Al2(SO4)3 + 6HCl 5/267 = x/342; x = (5*342)/267 = 6.4 гр; 5/267 = y/219; y = (5*219)/267 = 4.1 л