Сократите дробь 3а2-5а-2/а2-5а+6

Question

Сократите дробь 3а2-5а-2/а2-5а+6

Answer 1

3a²-5a-3=0
D=25-4*3*(-3)=25+24=49
a= (5+7)/6=12/6=2
a=(5-7)/6= -2/6= -1/3
3a²-5a-3=3(a+1/3)(a-2)=(3a+1)(a-2)

а²-5а+6=0
D=25-4*6=1
a=(5+1)/2=6/2=3
a=(5-1)/2=4/2=2
а²-5а+6=(a-3)(a-2)

3a²-5a-3/а²-5а+6=(3a+1)(a-2) / (a-3)(a-2)=
=(3a+1) / (a-3)