Sin 870*-5cos840*= найти sin2a, если sin a=-0,8, a€lll

Решите задачу:

$1)sin870-5cos840=0.5-2.5=-2 \\ sin870=sin(720+150)=sin150=sin(180-30) =\\ =sin30= \frac{1}{2}=0.5 \\ \\ 5cos840=5cos(720+120)=-5cos120=-5cos(180-60)= \\ =5cos60=5* \frac{1}{2} = \frac{5}{2} =2.5 \\$

$2)sin2a=2sinacosa=2*(-0.8)*0.6=-0.96 \\ \\ sina=-0.8 \\ \\ cosa= \sqrt{1-sin ^{2} a} = \sqrt{1-(-0.8) ^{2} } = \sqrt{1-0.64} = \sqrt{0.36} =0.6$