Помогите решить 17/64+(9/16+33/64)=

Решение:

$\boldsymbol{ \dfrac{17}{64} +( \dfrac{9}{16} + \dfrac{33}{64} ) = 1 \dfrac{11}{32}}\\ \\ \\ \\ 1) \dfrac{9^{\cdot4}}{16^{\cdot4}} + \dfrac{33^{\cdot1}}{64^{\cdot1}} = \dfrac{36+33}{64} = \dfrac{69}{64}. \\ \\ \\ 2) \dfrac{17}{64}+\dfrac{69}{64} = \dfrac{17+69}{64} = \dfrac{86^{:2}}{64^{:2}} = \dfrac{43}{32} = 1 \dfrac{11}{32}. \\ \\ \\ \\ \boldsymbol{\boxed{OTBET:1 \dfrac{11}{32}}}$