Дано
m(NH2-CH2-COOH) = 89 g
m практ(NH2-CH2-COONa) = 100 g
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W(NH2CH2COONa)-?
89 Xg
NH2CH2COOH+KOH-->NH2CH2COONa+H2O
75 97
M(NH2CH2COOH) = 75 g/mol
M(NH2CH2COONa)= 97 g/mol
X = 89*97 / 75 = 115.1 g
W(NH2CH2COONa) = 100 / 115.1 * 100% = 86.88%
ответ 86.88 %