2cosx sinx= -1/2 ребятки - помогите
Sin2x= - 1/2 2x = arcsin ( - 1/2) 2x = - π/6 х= - π/12
Решение 2cosx sinx= -1/2 sin2x = - 1/2 2x = (-1)^n * arcsin(-1/2) + πn, n ∈ Z 2x = (-1)^(n+1) * arcsin(1/2) + πn, n ∈ Z 2x = (-1)^(n+1) * (π/6) + πn, n ∈ Z x = (-1)^(n+1) * (π/12) + πn/2, n ∈ Z