X(x+3)-6<3(x+1) решите пожалуйста

$x(x+3)-6\ \textless \ 3(x+1)\\\\ x^2+3x-6\ \textless \ 3x+3\\\\ x^2-9\ \textless \ 0\\\\ x^2-3^2\ \textless \ 0\\\\ (x-3)*(x+3)\ \textless \ 0\\\\ \left \{ {{x-3\ \textgreater \ 0} \atop {x+3\ \textless \ 0}} \right. \ \ or\ \ \left \{ {{x-3\ \textless \ 0} \atop {x+3\ \textgreater \ 0}} \right.\\\\ \left \{ {{x\ \textgreater \ 3} \atop {x\ \textless \ -3}} \right. \ \ or\ \ \left \{ {{x\ \textless \ 3} \atop {x\ \textgreater \ -3}} \right.\\\\ \left \{ {{x\ \textless \ 3} \atop {x\ \textgreater \ -3}} \right.\\\\ -3\ \textless \ x\ \textless \ 3\\\\ x\in(-3;\ 3)$

Ответ: $(-3;\ 3)$