Помогите решить 2 задания! все во вложениях!

1) $\left \{ {{10-2x \geq 9-x} \atop {-5x^2+8x-43 \geq -4x^2-5x-1}} \right. \\\ \left \{ {{-x \geq -1} \atop {x^2-13x+42 \leq 0}} \right. \\\ \left \{ {{x \leq 1} \atop {(x-6)(x-7) \leq 0}} \right. \\\ \left \{ {{x \leq 1} \atop {6 \leq x \leq 7}} \right.$
Ответ: нет решений

2) $\left \{ {{6x+1 \leq 5x-3} \atop {12-2x \geq 10-x}} \right. \\\ \left \{ {{x \leq -4} \atop {-x \geq -2}} \right. \\\ \left \{ {{x \leq -4} \atop {x \leq 2}} \right. \\\ x \leq -4$
Ответ: x<=-4</u>