Найдите производную.

Решите задачу:

$f(x)=2 \sqrt{x} (5-x) \\ \\ f'(x)=2* \frac{1}{2} * \frac{5-x}{ \sqrt{x} } -2 \sqrt{x} = \frac{5-3x}{ \sqrt{x} } \\ \\ f'(100)= \frac{5-300}{ \sqrt{100} } = \frac{-295}{10} =-29.5 \\ \\$

$f(x)= \frac{6x-3}{5-3x} \\ \\ f'(x)= \frac{6(5-3x)+3(6x-3)}{(5-3x)^2} = \frac{21}{(5-3x)^2} \\ \\ f'(2)= \frac{21}{(5-6)^2} =21 \\ \\$

$f(x)= \frac{x^2}{x-1} \\ \\ f'(x)= \frac{2x(x-1)-x^2}{(x-1)^2} = \frac{x^2-2x}{(x-1)^2} \\ \\ f'(0)=0 \\$