0\\ y=(x+7)(x+3)\\ D(y)=R\\ \left[\begin{gathered} x=-7\\ x=-3
\end{gathered}\right." alt="(x+7)(x+3)>0\\ y=(x+7)(x+3)\\ D(y)=R\\ \left[\begin{gathered} x=-7\\ x=-3 \end{gathered}\right." align="absmiddle" class="latex-formula">
По методу интервалов находим
-3 \end{gathered}\right.\\ x \in (-\infty;-7)\cup(-3;+\infty)" alt=" \left[\begin{gathered} x<-7\\ x>-3 \end{gathered}\right.\\ x \in (-\infty;-7)\cup(-3;+\infty)" align="absmiddle" class="latex-formula">