Найдите значение выражения

Решите задачу:

$(2\frac{2}{3}-4\frac{3}{4})*19.2=(2+\frac{2}{3}-4-\frac{3}{4})*19.2=\\\\ =(2-4+\frac{2}{3}-\frac{3}{4})*\frac{192}{10}=(-2+\frac{2}{3}-\frac{3}{4})*\frac{96*2}{5*2}=\\\\ =(-\frac{2*3*4}{3*4}+\frac{2*4}{3*4}-\frac{3*3}{4*3})*\frac{96}{5}=\\\\ =\frac{-2*3*4+2*4-3*3}{4*3*1}*\frac{8*4*3}{5}=\\\\ =\frac{-24+8-9}{1}*\frac{8}{5}=\frac{-25}{1}*\frac{8}{5}=\\\\ =-\frac{25*8}{5}=-\frac{5*5*8}{5*1}=-\frac{5*8}{1}=-5*8=-40$