Помогите решить пять уравнений

Question

Помогите решить пять уравнений

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Answer 1

А) 
 дано
m(P2O5) = 71 g
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m(H3PO4)-?

P2O5+3H2O-->2H3PO4
M(P2O5) = 142 g/mol
n(P2O5) = m / M = 71 / 142 = 0.5 mol
n(P2O5) = 2n(H3PO4)
n(H3PO4) = 2*0.5 = 1 mol
M(H3PO4)= 98 g/mol
m(H3PO4) = n*M = 1*98 = 98 g
ответ 98 г

Б) дано
m(СO2) = 88 g
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m(CO2)-?

CO2+H2O-->H2CO3
M(CO2 ) = 44 g/mol
n(CO2) = m / M = 88 / 44 = 2 mol
n(CO2) = n(H2CO3) = 2 mol
M(H2CO3)= 62 g/mol
m(H2CO3) = n*M = 2*62 = 124 g
ответ 124 г

в)
дано
V(CO2) = 89.6 L
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m(H2CO3)-?

CO2+H2O-->H2CO3
n(CO2) = V / Vm= 89.6 / 22.4 = 4 mol
n(CO2) = n(H2CO3) = 4 mol
M(H2CO3)= 62  g/mol
m(H3CO3) = n*M = 4*62 = 248 g
ответ 248 г

г)
дано
m(B2O3) = 100 g
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m(H3BO3)-?

B2O3+3H2O-->2H3BO3
M(B2O3) = 70 g/mol
n(B2O3) = m / M = 100 / 70 = 1.43 mol
n(B2O3) = 2n(H3BO3)
n(H3BO3) = 2*1.43 = 2.86 mol
M(H3BO3)= 62 g/mol
m(H3BO3) = n*M = 2.86*62 = 177.32  g
ответ 177.32 г

д)

дано
m(SO3) = 320 g
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m(H2SO4)-?

SO3+H2O-->H2SO4
M(SO3) = 80 g/mol
n(SO3) = m / M = 320 / 80 = 4 mol
n(SO3) = n(H2SO4) = 4 mol
M(H2SO4)= 98 g/mol
m(H2SO4) = n*M = 4*98 = 392 g
ответ 392 г

Answer 2

A) m (H3PO4) = 98г

б) m (H2CO3) = 124г

в) m (H2CO3) = 248г

г) m (H3BO3) = 177.196г

д) m (H2SO4) = 392г

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Peшения:

а) P2O5 + 3H2O = 2H3PO4

n (P2O5) = m/M = 71 / 142 = 0.5 моль
n (H3PO4) = 2n (P2O5) = 1 моль (по УХР)
m (H3PO4) = n * M = 1 * 98 = 98г

б) CO2 + H2O = H2CO3

n (CO2) = m/M = 88 / 44 = 2 моль
n (H2CO3) = n (CO2) = 2 моль (по УХР)
m (H2CO3) = n * M = 2 * 62 = 124г

в) CO2 + H2O = H2CO3

n (CO2) = V/Vm = 89.6 / 22.4 = 4 моль
n (H2CO3) = n (CO2) = 4 моль (по УХР)
m (H2CO3) = n * M = 4 * 62 = 248г

г) B2O3 + 3H2O = 2H3BO3

n (B2O3) = m/M = 100 / 70 = 1.429 моль
n (H3BO3) = 2n (B2O3) = 2.858 моль (по УХР)
m (H3BO3) = n * M = 2.858 * 62 = 177.196г

д) SO3 + H2O = H2SO4

n (SO3) = m/M = 320 / 80 = 4 моль
n (H2SO4) = n (SO3) = 4 моль (по УХР)
m (H2SO4) = n * M = 4 * 98 = 392г