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Решите задачу:

$\frac{ {x}^{2} + 6x - 7}{ |x + 4| } < 0$

$\frac{ {x}^{2} + 6x - 7}{ |x + 4| } < 0\\\\ \left \{ {{x^2+6x-7\ \textless \ 0} \atop {x \neq -4}} \right. \\\\ \left \{ {{x^2+7x-x-7\ \textless \ 0} \atop {x \neq -4}} \right. \\\\ \left \{ {{x(x+7)-(x+7)\ \textless \ 0} \atop {x \neq -4}} \right. \\\\ \left \{ {{(x-1)(x+7)\ \textless \ 0} \atop {x \neq -4}} \right. \\\\ \left \{ {{-7\ \textless \ x\ \textless \ 1} \atop {x \neq -4}} \right. \\\\ x\in(-7;\ -4)\cup(-4;\ 1)$