Сколько надо сжечь природного газа, чтобы нагреть 10л воды на 10 градусов? Заранее благодарю.
Дано: q = 33.5 × 10⁶ Дж/кг, V = 10⁻² м³, Δt = 10°C Найти: m - ? Решение: Ответ: m = 12.5 г
![Q_{1} = Q_{2} \ ; \ Q_{1} = q * m \ ; \ Q_{2} = cm_{1} \Delta t \ ; \ m_{1} = \rho V\\ \\ qm = c\rho V \Delta t \ ; \ \rightarrow \ m = \dfrac{c\rho V \Delta t}{q} \\ \\ m = \dfrac{4200*1000*10^{-2}*10}{33.5*10^{6}} = 0.0125 \ [kg] = 12.5 \ [g]](https://tex.z-dn.net/?f=Q_%7B1%7D+%3D+Q_%7B2%7D+%5C+%3B+%5C+Q_%7B1%7D+%3D+q+%2A+m+%5C+%3B+%5C+Q_%7B2%7D+%3D+cm_%7B1%7D+%5CDelta+t+%5C+%3B+%5C+m_%7B1%7D+%3D+%5Crho+V%5C%5C+%5C%5C+qm+%3D+c%5Crho+V+%5CDelta+t+%5C+%3B+%5C+%5Crightarrow+%5C+m+%3D++%5Cdfrac%7Bc%5Crho+V+%5CDelta+t%7D%7Bq%7D+%5C%5C+%5C%5C+m+%3D++%5Cdfrac%7B4200%2A1000%2A10%5E%7B-2%7D%2A10%7D%7B33.5%2A10%5E%7B6%7D%7D+%3D+0.0125+%5C+%5Bkg%5D+%3D+12.5+%5C+%5Bg%5D+ "Q_{1} = Q_{2} \ ; \ Q_{1} = q * m \ ; \ Q_{2} = cm_{1} \Delta t \ ; \ m_{1} = \rho V\\ \\ qm = c\rho V \Delta t \ ; \ \rightarrow \ m = \dfrac{c\rho V \Delta t}{q} \\ \\ m = \dfrac{4200*1000*10^{-2}*10}{33.5*10^{6}} = 0.0125 \ [kg] = 12.5 \ [g]")