(0,03)⁴ * (2^8 - 4²)³ = - Все ответы

Решите задачу:

$(0.03)^4*(2^8-4^2)^3=\\\\ =(\frac{3}{100})^4*[2^{2*4}-4^2]^3=\\\\ =\frac{3^4}{100^4}*[(2^2)^4-4^2]^3=\\\\ =\frac{3^4}{25^4*4^4}*[4^4-4^2]^3=\\\\ =\frac{3^4}{25^4*4^4}*[4^2*(4^2-1)]^3=\\\\ =\frac{3^4}{25^4*4^4}*4^6*15^3=\\\\ =\frac{3^4*4^6*5^3*3^3}{5^8*4^4}=\\\\ =\frac{3^7*4^2}{5^5}=\frac{2187*16}{25^2*5}=$

$=\frac{2187*16}{25^2*5}=\frac{2187*16*4^2*20}{25^2*4^2*5*20}=\\\\ =\frac{2187*256*20}{100^2*100}=\frac{2187*512}{100^2*10}=\\\\ =\frac{1119744}{100000}=11.19744$