Задание - сократить.2^{2n+3} * 3^{3n+3}/4^{n} * 27^{n+2}. 2^{2n+3} * 3^{3n+3} -...

Решите задачу:

$\frac{2^{2n+3} * 3^{3n+3}}{4^{n} * 27^{n+2} } = \frac{2^{2n+3} * 3^{3n + 3}}{(2^2)^n * (3^3)^{n+2}} = \frac{2^{2n+3} * 3^{3n + 3}}{2^{2n} *3^{3n+6}} = \\ \\ = 2^{2n+3-2n} * 3^{3n+3-(3n+6)} = 2^3 * 3^{3n+3-3n-6} = \\ \\ =2^3*3^{-3} = \frac{2^3}{3^3} = \frac{2*2*2}{3*3*3}= \frac{8}{27} \\ \\$