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M (Al(OH)3) = 27 + (16 + 1) * 3 = 78 г/моль ω (Al) = M (Al) : M (Al(OH)3) * 100% = 27 ÷ 78 * 100% = 34,615% ω (O) = M (3O) : M (Al(OH)3) * 100% = 48 : 78 * 100% = 61,539% ω (H) = M (3H) : M (Al(OH)3) * 100% = 3 ÷ 78 * 100% = 3,846%