Реши систему уравнений методом подстановки.

{ 5 - 5(0.2t-2z) = 3(3z +2) + 2t
{4(z - 5t) - (2z +t) =10 - 2(2z +t)

{ 5 - 5*0.2t - 5*(-2z)= 3*3z +3*2 + 2t
{4z + 4*(-5t) - 2z -t = 10 - 2*2z - 2t

{ 5 - t + 10z = 9z +6 + 2t
{ 4z - 20t - 2z - t = 10 - 4z - 2t

{ -t + 10z - 9z - 2t = 6 - 5
{ 2z - 21t + 4z + 2t = 10

{ -3t + z = 1 ⇒ z = 1 + 3t
{ -19t + 6z = 10
- 19t + 6(1 + 3t) = 10
- 19t + 6 + 18t = 10
- t + 6 = 10
-t = 10 - 6
-t = 4
t = - 4

z = 1 + 3*(-4) = 1 - 12
z = - 11

Ответ:
z = - 11
t = - 4