3 5/15+(d-1 7/16)=9 1/16 пж помогите решить

Решите задачу:

$3 \frac{5}{15} + (d - 1 \frac{7}{16} ) = 9 \frac{1}{16} \\ d - 1 \frac{7}{16} = 9 \frac{1}{16} - 3 \frac{5}{15} = \frac{145}{16} - \frac{50}{15} = \frac{2175 - 800}{240} = \frac{1375}{240} \\ d = \frac{1375}{240} + 1 \frac{7}{16} = \frac{1375}{240} + \frac{23}{16} = \frac{1375 + 345}{240} = \frac{1720}{240} = \frac{172}{24} = 7 \frac{4}{24} = 7 \frac{1}{6}$