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Решите задачу:

$\frac{ \sqrt{104} }{ \sqrt{26} } = \frac{ \sqrt{26 \sqrt{4} } }{ \sqrt{26} } = \sqrt{4} = 2 \\$
$\sqrt{143 \sqrt{65 \sqrt{55} } } = \sqrt{143 \times 65 \times 55} = \sqrt{511225} = 715$
$\sqrt{250 {}^{2} } - 150 {}^{2} = \sqrt{(250 - 150) \times (250 + 150) = \sqrt{100 \times 400} } = 10 \times 20 = 200 \\$
$\sqrt{} \frac{10}{33} \div \sqrt{ \frac{5}{264} } = \sqrt{ \frac{10}{33} \div \frac{5}{264} } = \sqrt{16} = 4$
$\frac{ \sqrt{} 2000}{ \sqrt{32 \times \sqrt{40} } } = \frac{ \sqrt{2000} }{ \sqrt{1280} } = \frac{ \sqrt{25} }{ \sqrt{16} } = \frac{5}{ \sqrt{16} } = \frac{5}{4} = 1.25$
$\sqrt{392 {}^{2 + 294 {}^{2} } } = \sqrt{(4 \times 98) {}^{2} + (3 \times 98) {}^{2} } = \sqrt{4 {}^{2} \times 98 {}^{2} + (3 \times 98) {}^{2} } = \sqrt{4 {}^{2} \times 98 {}^{2} + 3 {}^{2} \times 98 {}^{2} } = \sqrt{2 {}^{2} \times 49 \ {}^{2} (2 {}^{2} \times 2 {}^{2} + 3 {}^{2} ) } = \sqrt{ {2}^{2} \times {49}^{2} \times ( {2}^{4} + 3 {}^{2} ) } = \sqrt{ {2}^{2} \times {49}^{2} \times 25 } = 2 \times 49 \times 5 = 490$