Вопрос в картинках...

Решите задачу:

$\left \{ {{7x-4y=2} \atop {5x+11y=43}} \right. \left \{ {{x= \frac{2+4y}{7} } \atop {5 (\frac{2+4y}{7}) +11y=43}} \right. \left \{ {{x= \frac{2+4y}{7} } \atop {\frac{10+20y}{7} +11y=43}} \right. \left \{ {{x= \frac{2+4y}{7} } \atop {{10+20y+77y=301$
$\left \{ {{x= \frac{2+4y}{7} } \atop {{10+97y=301}} \right. \left \{ {{x= \frac{2+4y}{7} } \atop {{y= \frac{291}{97}=3 }} \right. \left \{ {{x= \frac{2+4*3}{7} } \atop {{y=3}} \right. \left \{ {{x= \frac{14}{7}=2 } \atop {{y=3}} \right. \left \{ {{x= 2 } \atop {{y=3}} \right.$