(x-0,5):2 3\4=1n3\11:5\7 0,3(5x+0,2)=-2,6-(2,7x-1,4)

Решите задачу:

$(x-0,5):2 \frac{3}{4}=1 \frac{3}{11} : \frac{5}{7} \\\\ (x-0,5):2 \frac{3}{4}=\frac{14}{11} * \frac{7}{5} \\\\ (x-0,5):2 \frac{3}{4}=\frac{98}{55} \\\\ x - 0,5 = \frac{98}{55} * \frac{11}{4} \\\\ x - 0,5 = \frac{49}{10} =4,9\\\\ x = 4,9+0,5\\\\ x=5,4$

$2) 0,3(5x+0,2)=-2,6-(2,7x-1,4)\\\\ 1,5x + 0,06 = -2,6-2,7x+1,4\\\\ 1,5x + 2,7x = -1,2-0,06\\\\ 4,2x = -1,26\\\\ x = -1,26 : 4,2\\\\ x = -0,3$