Дано
m(C2H2) = 150 g
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m(CO2)-?
2C2H2+5O2-->4CO2+2H2O
M(C2H2) = 28 g/mol
n(C2H2) = m/M = 150 / 28 = 5.36 mol
2n(C2H2) = 4n(CO2)
n(CO2) = 4*5.36 / 2 = 10.72 mol
M(CO2) = 44 g/mol
m(CO2) = n*M = 10.72 * 44 = 471.68 g
ответ 471.68 г