Х2-49>0 ребят помогите пожалуйста, очень нужно

$x^2-49\ \textgreater \ 0\\\\ x^2-7^2\ \textgreater \ 0\\\\ (x-7)*(x+7)\ \textgreater \ 0\\\\ \left \{ {{x-7\ \textgreater \ 0} \atop {x+7\ \textgreater \ 0}} \right. OR \left \{ {{x-7\ \textless \ 0} \atop {x+7\ \textless \ 0}} \right. \\\\ \left \{ {{x\ \textgreater \ 7} \atop {x\ \textgreater \ -7}} \right. OR \left \{ {{x\ \textless \ 7} \atop {x\ \textless \ -7}} \right. \\\\ x\ \textgreater \ 7\ \ OR\ \ x\ \textless \ -7\\\\ x\in(7;\ +\infty)\ \ OR\ \ x\in(-\infty;\ -7)\\\\ x\in(7;\ +\infty)\cup(-\infty;\ -7)\\\\ x\in(-\infty;\ -7)\cup(7;\ +\infty)$

Ответ: $(-\infty;\ -7)\cup(7;\ +\infty)$