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$\frac{(49 \frac{5 }{24} -46 \frac{7}{20} {) \div 2 \frac{1}{3} + 0.6} }{0.2} = 9.125\\ 1) \: 49 \frac{5}{24} - 46 \frac{7}{20} = 49 \frac{25}{120} - 46 \frac{42}{120} = \\ = 48 \frac{145}{120} - 46 \frac{42}{120} = 2 \frac{103}{120} \\ 2) \: 2 \frac{103}{120} \div 2 \frac{1}{3} = \frac{343 \times 3}{120 \times 7} = \frac{343 \times 1}{40 \times 7} = \\ = \frac{49}{40} = 1 \frac{9}{40} \\ 3) \: 1 \frac{9}{40} + 0.6 = 1 \frac{9}{40} + \frac{6}{10} = 1 \frac{9}{40} + \frac{24}{40} = \\ = 1 \frac{33}{40} \\ 4) \: 1 \frac{33}{40} \div 0.2 = 1 \frac{33}{40} \div \frac{1}{5} = \frac{73\times 5}{40} = \frac{73}{8} = \\ = 9 \frac{1}{8} = 9.125$