Tg(180°+30°)×tg(270°-30°)-sin(180°+30°)×cos(90°+30°)=¿ срочно пожалуйста

Question

Tg(180°+30°)×tg(270°-30°)-sin(180°+30°)×cos(90°+30°)=¿
срочно пожалуйста

Answer 1

Tg210*tg240-sin210*cos120=(1/√3)*√3-(-1/2)(-1/2)=1-1/4=3/4

Answer 2

Tg30°x ctg30°- sin30°x sin30°= √3/3 x √3 - 1/2 x 1/2 = 9/12= 3/4