Cos (2П-x)+sin(П:2+x)=

Question

Cos (2П-x)+sin(П:2+x)=

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Answer 1

По формулам приведения
cos(2π-x)=cosx
sin((π/2)+x)=cosx
cosx+cosx=√2
2cosx=√2
cosx=(√2)/2
x=+-(arccos(√2)/2)+2πn, n∈Z
x=+-(π/4)+2πn, n∈Z