Выразить одно неизвестное через другое в уравнении 2x+y=-35x-2y=11/2x+3y=5-x+5/3y=15

1)
$2x + y = - 3 \\ y = - 3 - 2x$
$2x + y = - 3 \\ 2x = - 3 - y \\ x = - 1.5 - 0.5y$
2)
$5x - 2y = 1 \\ 5x = 1 + 2y \\ x = 0.2 + 0.4y$
$5x - 2y = 1 \\ - 2y = 1 - 5x \\ y = - 0.5 + 2.5x$
3)
$\frac{1}{2} x + 3y = 5 \\ \frac{1}{2} x = 5 - 3y \\ x = 10 - 6y$
$\frac{1}{2} x + 3y = 5 \\ 3y = 5 - \frac{1}{2} x \\ y = \frac{5}{3} - \frac{1}{6} x$
4)
$- x + \frac{5}{3} y = 15 \\ x = - 15 + \frac{5}{3} y$
$- x + \frac{5}{3} y = 15 \\ \frac{5}{3} y = 15 + x \\ y = 9 + \frac{3}{5} x$