Привести к функции y=f(x): x^2+(y+1)^2+5=21

Question

Привести к функции y=f(x):
x^2+(y+1)^2+5=21

Answer 1

X^2+(y+1)^2=16
(y+1)^2=16-x^2
y+1=+-sqrt(16-x^2)
y=+-sqrt(16-x^2)-1