log_{9} (11-x)\\ \\ ODZ:\left \{ {{x+3>0} \atop {11-x>0}} \right. \left \{ {{x>-3} \atop {x<11}} \right.\\ \\ x\in(-3;11)\\ \\ 9>1\\ \\ x+3>11-x\\ \\ 2x>8;x>4\\ \\ " alt=" log_{9} (x+3)>log_{9} (11-x)\\ \\ ODZ:\left \{ {{x+3>0} \atop {11-x>0}} \right. \left \{ {{x>-3} \atop {x<11}} \right.\\ \\ x\in(-3;11)\\ \\ 9>1\\ \\ x+3>11-x\\ \\ 2x>8;x>4\\ \\ " align="absmiddle" class="latex-formula">
с учетом одз,получаем ответ: x∈(4;11)