Срочно!!! Найти производные функций

Решите задачу:

$1.y' =2sinxcosx*lnx+ \frac{sin^2x}{x} =sin2x*lnx+ \frac{sin^2x}{x} \\\\ 2.y'= \frac{(2x+2)(3-4x)-(x^2+2x)(-4)}{(3-4x)^2} = \frac{-2x-8x^2+6+4x^2+8x}{(3-4x)^2} = \frac{-4x^2+6x+6}{(3-4x)^2} \\\\ 3.y'= \frac{(ctg^3x)'}{ctg^3x} =- \frac{3ctg^2x}{sin^2xctg^3x} =- \frac{3}{sinxcosx} =- \frac{6}{sin2x} \\ y'( \frac{ \pi }{4} )=- \frac{6}{sin( \frac{\pi}{2} } =-6$

$5. log_5y=3x^3+x\\\\ \frac{y'}{y*ln5} =9x^2+1\\\\ y'=5^{3x^3+x}(9x^2+1)ln5\\\\ 7.y'= \frac{( \frac{x-1}{x+1} )'}{1+( \frac{x-1}{x+1} )^2} = \frac{ \frac{2}{(x+1)^2} }{ \frac{x^2+2x+1+x^2-2x+1}{(x+1)^2} } = \frac{1}{x^2+1}$