1) ΔMAO-прямоугольный
cosMAO=AO/AM
AM=4
AO=(2/3)AK
AK^2=6^2-3^2=36-9=27
AK=3√3
AO=(2/3)*3√3=2√3
CosMAO=2√3/4=√3/2
2)tgMKO=MO/OK
OK=AK-OA=3√3-2√3=√3
MO^2=AM^2=AO^2=6^2-(2√3)^2=36-12=24
MO=2√6
tgMOK=2√6/√3=2√2
3)KM^2=MO^2+OK^2=24+3=27; KM=3√3
S=3S(ΔBCM)=3*BC*KM/2=3*6*3√3/2=27√3