1/5^4x-17 >=125 решите неравенство

Question

1/5^4x-17 >=125 решите неравенство

Answer 1

(1/5)^(4х-17)≥125
5^(17-4х)≥5³
17-4х≥3
-4х≥-14
х≤14/4
х≤7/2
х≤3,5

Answer 2

5^(-4x+17) >=5^3

-4x+17>=3

-4x>=-14

4x>=14

x>=14/4

x>=7/2

x>=3,5

[3,5;+oo)