Решение:


Пусть
0 " alt=" 2^{x} = t, t > 0 " align="absmiddle" class="latex-formula">, тогда


0, t + 1 > 0, " alt=" t > 0, t + 1 > 0, " align="absmiddle" class="latex-formula"> тогда

Получили, что


Так как 2 > 1, то x < 2,
x∈ (- ∞ ; 2).
Ответ: (- ∞ ; 2).