2^(m+1) + 2^(-m+1) = 2^(m+1) + 1/2^(m-1) = [2^(m+1)*2^(m-1)+1]/2^(m-1)= (2^(2m) + 1)/2^(m-1)= (4^m+1)/2^(m-1)
(4^m+1)(3^(m+2)+3^(m+1)) = (4^m +1)3^(m+1)(1+3)=4*3^(m+1)(4^m+1)
(4^m+1)/2^(m-1) : (4*3^(m+1)(4^m+1)) = 1/(4*2^(m-1)(3^(m+1)) = 1/(4*2^m/2*3^m*3) = 1/(6*6^m) = 1/6^(m+1) = 6^-(m+1) = 6^(-m-1)
Ответ С