6/(х + 1) - 1/(х-1) = 1 | * (x + 1)(x - 1)
6(x -1) - 1(x+1) = 1*(x+1)(x-1)
6x - 6 -x - 1 = x^2 - 1^2
5x - 7 = x^2 - 1
x^2 - 1 - 5x + 7 = 0
x^2 - 5x + 6 = 0
D = (-5)^2 - 4*1 *6 = 25 - 24 = 1
D>0 - два корня уравнения
х1 = ( - (-5) - √1) / (2*1) = (5 -1)/2 = 4/2 = 2
х2 = (- (-5) + √1 ) / (2*1) = (5+1)/2 = 6/2 = 3
Ответ : х1 = 2 ; х2 = 3 .