15 баллов умаляю срочно упростите А)2х-2/х^2+9х-10Б)у^2-6у+8/у^2+3у-10...

Решите задачу:

$a) \: \frac{2x - 2}{ {x}^{2} + 9x - 10 } = \frac{2(x - 1)}{(x + 10)(x - 1)} = \frac{2}{x + 10} \\$

$b) \: \frac{ {y}^{2} - 6y + 8}{ {y}^{2} + 3y - 10} = \frac{(y - 2)(y - 4)}{(y - 2)(y + 5)} = \frac{y - 4}{y + 5} \\$

$c) \: \frac{2 {x}^{2} + 2x - 12}{4 {x}^{2} + 12x} = \frac{2(x - 2)(x + 3)}{4x(x + 3)} = \frac{x - 2}{2x} \\$

$d) \: \frac{3x - 6}{2 {x}^{2} + x - 10} = \frac{3(x - 2)}{(2x + 5)(x - 2)} = \frac{3}{2x + 5} \\$