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$\frac{( - 20 \frac{3}{5} + 21.7) \times | - 1 \frac{1}{7} | }{(32 \frac{8}{5} + ( - 29 \frac{3}{5})) \div \frac{11}{25} } - ( - 17) = 17 \frac{121}{875} \\ - - - - - - - - \\ 1) \: \: \: - 20 \frac{3}{5} + 21.7 = - 20 \frac{3}{5} + 21 \frac{7}{10} = 21 \frac{7}{10} - 20 \frac{6}{10} = 1 \frac{1}{10} \\ 2) \: \: \: 1 \frac{1}{10} \times | - 1 \frac{1}{7} | = \frac{11}{10} \times \frac{8}{7} = \frac{11 \times 4}{5 \times 7} = \frac{44}{35} = 1 \frac{9}{35} \\ 3) \: \: \: 32 \frac{8}{5} + ( - 29 \frac{3}{5} ) = 3 \frac{8 - 3}{5} = 3 \frac{5}{5} = 4 \\ 4) \: \: \: 4 \div \frac{11}{25} = \frac{4 \times 25}{11} = \frac{100}{11} = 9 \frac{1}{11} \\ 5) \: \: \: 1 \frac{9}{35} \div 9 \frac{1}{11} = \frac{44}{35} \div \frac{100}{11} = \frac{44 \times 11}{35 \times 100} = \frac{11 \times 11}{35 \times 25} = \frac{121}{875} \\ 6) \: \: \: \frac{121}{875} - ( - 17) = \frac{121}{875} + 17 = 17 \frac{121}{875}$