0 \\ log_{2}(x) + \frac{1}{2} log_{2}(x) + \frac{1}{4} log_{2}(x) = 7 \\ \frac{7}{4} log_{2}(x) = 7 \\ log_{2}(x) = 4 \\ x = {2}^{4} = 16 \\ \sqrt{x} - 2 = \sqrt{16} - 2 = 4 - 2 = 2" alt=" log_{2}(x) + log_{4}(x) + log_{16}(x) = 7 \\ x > 0 \\ log_{2}(x) + \frac{1}{2} log_{2}(x) + \frac{1}{4} log_{2}(x) = 7 \\ \frac{7}{4} log_{2}(x) = 7 \\ log_{2}(x) = 4 \\ x = {2}^{4} = 16 \\ \sqrt{x} - 2 = \sqrt{16} - 2 = 4 - 2 = 2" align="absmiddle" class="latex-formula">