1.Представьте в виде степени с основанием x выражение 1)(x⁶)² 2.Упростите выражение...

1)
${( {x}^{6} )}^{2} = {x}^{6 \times 2} = {x}^{12}$
2)
1.
$(x - 2)(x - 11) - 2x(4 - 3x) = {x}^{2} - 2x - 11x + 22 - 8x + 6 {x}^{2} = 7 {x}^{2} - 21x + 22$
2.
$(a + 6)(a - 3) + (a - 4)(a + 5) = {a}^{2} + 6a - 3a - 18 + {a}^{2} - 4a + 5a - 20 = 2 {a}^{2} + 4a - 38$
3)
$8a - 12b = 4(2a - 3b)$
$3a - ab = a(3 - b)$
4)
$5a + 5b - am - bm = 5(a + b) - m(a + b) = (a + b)(5 - m)$
$6m - mn - 6 + n = m(6 - n) - (6 - n) = (6 - n)(m - 1)$
5)
${a}^{2} + 8a + 16 = {a}^{2} + 2 \times a \times 4 + {4}^{2} = {(a + 4)}^{2}$
$9 {x}^{2} - 6x + 1 = {(3x)}^{2} - 2 \times 3x \times 1 + 1 = (3x - 1) ^{2}$
6)
${x}^{2} - 4 = (x - 2)(x + 2)$
$25 - 9 {a}^{2} = (5 - 3a)(5 + 3a)$
7)
${c}^{3} + 8 = (c + 2)( {c}^{2} - 2c + 4)$
$27 {a}^{3} - {b}^{3} = (3a - b)(9 {a}^{2} + 3ab + {b}^{2} )$